3x-0.3x^2=5

Solution for 3x-0.3x^2=5 equation:

3x-0.3x^2=5

We move all terms to the left:

3x-0.3x^2-(5)=0

a = -0.3; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·(-0.3)·(-5)
Δ = 3
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{3}}{2*-0.3}=\frac{-3-\sqrt{3}}{-0.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{3}}{2*-0.3}=\frac{-3+\sqrt{3}}{-0.6}
$